Substitution method for Solving linear Systems
Substitution method
for Solving linear Systems
The Substitution method for Solving linear Systems is easy to solve the equations.
Substitution method can be applied in below steps.
Step 1: First select one equation and solve it for one variable either x = or y =.
Step 2: Substitute the solution from step 1 into the other equation.
Step 3: Solve the new equation.
Step 4: Substitute the value in equation and solve it for second variable.
Step 5: Check the solutions in both original equations.
Solve the following pair of linear equations by substitution method.
Example: (1) x + y = 14
x – y = 4
Solution: let x + y = 14……(1)
x – y = 4…….(2)
Step 1: Solve one of the equations for either x = or y =.
We will solve first equation for x
x + y = 14…..(1)
x = 14 – y
Step 2: Substitute the solution from step 1 into the other equation, that is equation 2.
x – y = 4……(2)
(14 – y) – y = 4
Step 3: Solve the new equation.
14 – y – y = 4
14 – 2y = 4
-2y = 4 – 14
-2y = -10
y = -10/-2
y = 5
Step 4: Substitute the value in equation and solve it for second variable.
x + y = 14
x + 5 = 14
x = 14 – 5
x = 9
Step 5: Check the solutions in both original
equations.
x + y = 14…..(1) x – y = 4…..(2)
9 + 5 = 14 9 – 5 = 4
14 = 14 4 = 4
The solution is (x, y) = (9, 5)
Example:(2) 2x + 5y = 12
4x – y = 2
Solution: let 2x + 5y = 12……(1)
4x – y = 2…….(2)
Step 1- Solve one of the equations for either x = or y =.
We will solve second equation for y
4x – y = 2…..(1)
-y = 2 – 4x
y = 4x – 2
Step 2- Substitute the solution from step 1 into the other equation, that is equation 1.
2x + 5y = 12……(1)
2x + 5(4x – 2) = 12
Step 3- solve the new equation.
2x + 20x – 10 = 12
22x = 12 = 10
22x = 22
x = 22/22
x = 1/1
x = 1
Step 4- Substitute the value in equation and solve it for second variable.
2x + 5y = 12
2 x 1 + 5y = 12
2 + 5y = 12
5y = 12 – 2
5y = 10
y = 10/5
y = 2
Step 5- Check the solutions in both original
equations.
2x + 5y = 12….(1) 4x – y = 2….(2)
2 x 1 + 5 x 2 = 12 4 x 1 – 2 = 2
2 + 10 = 12 4 = 4
The solution is (x, y) = (1, 2)
Example:(3) 2x – 9y = 0
x – 18y = 27
Solution: let 2x – 9y = 0…….(1)
x – 18y = 27…….(2)
Step 1- Solve one of the equations for either x = or y =.
We will solve second equation for x
x – 18y = 27…..(1)
x = 27 + 18y
Step 2- Substitute the solution from step 1 into the other equation, that is equation 1.
2(27 + 18y) – 9y = 0
Step 3- solve the new equation.
54 + 36y – 9y = 0
27y = – 54
y = – 54/27
y = – 2
y = – 2
Step 4- Substitute the value in equation and solve it for second variable.
2x – 9y = 0
2x – 9(-2) = 0
2x + 18 = 0
2x = -18
x = -18/2
x = -9
Step 5- Check the solutions in both original
equations.
2x – 9y = 0…..(1) x – 18y = 27…..(2)
2 x (-9) – 9 x (-2)= 0 -9 – 18 x (-2) = 27
-18 +18 = 0 -9 + 36 = 27
0 = 0 27 = 27
The solution is (x, y) = (-9, -2)