Divisibility Rule For 20 With Examples
Divisibility Rule For 20 With Examples
Divisibility Rule For 20
The divisibility rule for 20 is straightforward because it combines the rules for 4 and 5, since (20 = 4 x 5). For a number to be divisible by 20, it must satisfy both of these conditions.
Divisibility Rules for 4 and 5:
- Divisibility by 4:
- A number is divisible by 4 if the last two digits of the number form a number that is divisible by 4.
- Divisibility by 5:
- A number is divisible by 5 if its last digit is either 0 or 5.
Combining the Rules for 20:
For a number to be divisible by 20, it must:
- Have its last digit as 0 (to satisfy divisibility by 5).
- The last two digits must form a number that is divisible by 4.
Examples:
- Example: 160
- Last digit: 0 (satisfies the rule for 5).
- Last two digits: 60. Check if 60 is divisible by 4:
- (60/4 = 15) (which is an integer).
- Both conditions are satisfied, so 160 is divisible by 20.
- Example: 240
- Last digit: 0 (satisfies the rule for 5).
- Last two digits: 40. Check if 40 is divisible by 4:
- (40/4 = 10) (which is an integer).
- Both conditions are satisfied, so 240 is divisible by 20.
- Example: 85
- Last digit: 5 (satisfies the rule for 5).
- Last two digits: 85. Check if 85 is divisible by 4:
- (85/4 = 21.25) (not an integer).
- 85 is not divisible by 20.
- Example: 80
- Last digit: 0 (satisfies the rule for 5).
- Last two digits: 80. Check if 80 is divisible by 4:
- (80/4 = 20) (which is an integer).
- Both conditions are satisfied, so 80 is divisible by 20.
- Example: 45
- Last digit: 5 (satisfies the rule for 5).
- Last two digits: 45. Check if 45 is divisible by 4:
- (45/4 = 11.25) (not an integer).
- 45 is not divisible by 20.
Summary
To determine if a number is divisible by 20, check that:
- The last digit is 0 (for divisibility by 5).
- The last two digits form a number that is divisible by 4.
By applying these rules, we can quickly assess whether a number is divisible by 20.